3.15.69 \(\int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx\) [1469]

3.15.69.1 Optimal result
3.15.69.2 Mathematica [A] (verified)
3.15.69.3 Rubi [A] (verified)
3.15.69.4 Maple [A] (verified)
3.15.69.5 Fricas [A] (verification not implemented)
3.15.69.6 Sympy [A] (verification not implemented)
3.15.69.7 Maxima [A] (verification not implemented)
3.15.69.8 Giac [A] (verification not implemented)
3.15.69.9 Mupad [B] (verification not implemented)

3.15.69.1 Optimal result

Integrand size = 22, antiderivative size = 72 \[ \int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx=-\frac {155706083 x}{512}-\frac {149512931 x^2}{512}-\frac {130251491 x^3}{384}-\frac {95317731 x^4}{256}-\frac {54600291 x^5}{160}-\frac {7656993 x^6}{32}-\frac {6596235 x^7}{56}-\frac {1148175 x^8}{32}-\frac {10125 x^9}{2}-\frac {156590819 \log (1-2 x)}{1024} \]

output
-155706083/512*x-149512931/512*x^2-130251491/384*x^3-95317731/256*x^4-5460 
0291/160*x^5-7656993/32*x^6-6596235/56*x^7-1148175/32*x^8-10125/2*x^9-1565 
90819/1024*ln(1-2*x)
 
3.15.69.2 Mathematica [A] (verified)

Time = 0.01 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.04 \[ \int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx=\frac {263385079253}{860160}-\frac {155706083 x}{512}-\frac {149512931 x^2}{512}-\frac {130251491 x^3}{384}-\frac {95317731 x^4}{256}-\frac {54600291 x^5}{160}-\frac {7656993 x^6}{32}-\frac {6596235 x^7}{56}-\frac {1148175 x^8}{32}-\frac {10125 x^9}{2}-\frac {156590819 \log (1-2 x)}{1024} \]

input
Integrate[((2 + 3*x)^6*(3 + 5*x)^3)/(1 - 2*x),x]
 
output
263385079253/860160 - (155706083*x)/512 - (149512931*x^2)/512 - (130251491 
*x^3)/384 - (95317731*x^4)/256 - (54600291*x^5)/160 - (7656993*x^6)/32 - ( 
6596235*x^7)/56 - (1148175*x^8)/32 - (10125*x^9)/2 - (156590819*Log[1 - 2* 
x])/1024
 
3.15.69.3 Rubi [A] (verified)

Time = 0.19 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {99, 2009}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {(3 x+2)^6 (5 x+3)^3}{1-2 x} \, dx\)

\(\Big \downarrow \) 99

\(\displaystyle \int \left (-\frac {91125 x^8}{2}-\frac {1148175 x^7}{4}-\frac {6596235 x^6}{8}-\frac {22970979 x^5}{16}-\frac {54600291 x^4}{32}-\frac {95317731 x^3}{64}-\frac {130251491 x^2}{128}-\frac {149512931 x}{256}-\frac {156590819}{512 (2 x-1)}-\frac {155706083}{512}\right )dx\)

\(\Big \downarrow \) 2009

\(\displaystyle -\frac {10125 x^9}{2}-\frac {1148175 x^8}{32}-\frac {6596235 x^7}{56}-\frac {7656993 x^6}{32}-\frac {54600291 x^5}{160}-\frac {95317731 x^4}{256}-\frac {130251491 x^3}{384}-\frac {149512931 x^2}{512}-\frac {155706083 x}{512}-\frac {156590819 \log (1-2 x)}{1024}\)

input
Int[((2 + 3*x)^6*(3 + 5*x)^3)/(1 - 2*x),x]
 
output
(-155706083*x)/512 - (149512931*x^2)/512 - (130251491*x^3)/384 - (95317731 
*x^4)/256 - (54600291*x^5)/160 - (7656993*x^6)/32 - (6596235*x^7)/56 - (11 
48175*x^8)/32 - (10125*x^9)/2 - (156590819*Log[1 - 2*x])/1024
 

3.15.69.3.1 Defintions of rubi rules used

rule 99
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], 
 x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] && (IntegerQ[p] | 
| (GtQ[m, 0] && GeQ[n, -1]))
 

rule 2009
Int[u_, x_Symbol] :> Simp[IntSum[u, x], x] /; SumQ[u]
 
3.15.69.4 Maple [A] (verified)

Time = 0.85 (sec) , antiderivative size = 51, normalized size of antiderivative = 0.71

method result size
parallelrisch \(-\frac {10125 x^{9}}{2}-\frac {1148175 x^{8}}{32}-\frac {6596235 x^{7}}{56}-\frac {7656993 x^{6}}{32}-\frac {54600291 x^{5}}{160}-\frac {95317731 x^{4}}{256}-\frac {130251491 x^{3}}{384}-\frac {149512931 x^{2}}{512}-\frac {155706083 x}{512}-\frac {156590819 \ln \left (x -\frac {1}{2}\right )}{1024}\) \(51\)
default \(-\frac {10125 x^{9}}{2}-\frac {1148175 x^{8}}{32}-\frac {6596235 x^{7}}{56}-\frac {7656993 x^{6}}{32}-\frac {54600291 x^{5}}{160}-\frac {95317731 x^{4}}{256}-\frac {130251491 x^{3}}{384}-\frac {149512931 x^{2}}{512}-\frac {155706083 x}{512}-\frac {156590819 \ln \left (-1+2 x \right )}{1024}\) \(53\)
norman \(-\frac {10125 x^{9}}{2}-\frac {1148175 x^{8}}{32}-\frac {6596235 x^{7}}{56}-\frac {7656993 x^{6}}{32}-\frac {54600291 x^{5}}{160}-\frac {95317731 x^{4}}{256}-\frac {130251491 x^{3}}{384}-\frac {149512931 x^{2}}{512}-\frac {155706083 x}{512}-\frac {156590819 \ln \left (-1+2 x \right )}{1024}\) \(53\)
risch \(-\frac {10125 x^{9}}{2}-\frac {1148175 x^{8}}{32}-\frac {6596235 x^{7}}{56}-\frac {7656993 x^{6}}{32}-\frac {54600291 x^{5}}{160}-\frac {95317731 x^{4}}{256}-\frac {130251491 x^{3}}{384}-\frac {149512931 x^{2}}{512}-\frac {155706083 x}{512}-\frac {156590819 \ln \left (-1+2 x \right )}{1024}\) \(53\)
meijerg \(-\frac {156590819 \ln \left (1-2 x \right )}{1024}-6270 x \left (6 x +6\right )-\frac {34115 x \left (16 x^{2}+12 x +12\right )}{6}-\frac {21207 x \left (120 x^{3}+80 x^{2}+60 x +60\right )}{16}-\frac {90801 x \left (7680 x^{6}+4480 x^{5}+2688 x^{4}+1680 x^{3}+1120 x^{2}+840 x +840\right )}{7168}-\frac {11745 x \left (40320 x^{7}+23040 x^{6}+13440 x^{5}+8064 x^{4}+5040 x^{3}+3360 x^{2}+2520 x +2520\right )}{14336}-\frac {2025 x \left (71680 x^{8}+40320 x^{7}+23040 x^{6}+13440 x^{5}+8064 x^{4}+5040 x^{3}+3360 x^{2}+2520 x +2520\right )}{28672}-\frac {5148 x \left (192 x^{4}+120 x^{3}+80 x^{2}+60 x +60\right )}{5}-\frac {682281 x \left (2240 x^{5}+1344 x^{4}+840 x^{3}+560 x^{2}+420 x +420\right )}{8960}-12096 x\) \(217\)

input
int((2+3*x)^6*(3+5*x)^3/(1-2*x),x,method=_RETURNVERBOSE)
 
output
-10125/2*x^9-1148175/32*x^8-6596235/56*x^7-7656993/32*x^6-54600291/160*x^5 
-95317731/256*x^4-130251491/384*x^3-149512931/512*x^2-155706083/512*x-1565 
90819/1024*ln(x-1/2)
 
3.15.69.5 Fricas [A] (verification not implemented)

Time = 0.21 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.72 \[ \int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx=-\frac {10125}{2} \, x^{9} - \frac {1148175}{32} \, x^{8} - \frac {6596235}{56} \, x^{7} - \frac {7656993}{32} \, x^{6} - \frac {54600291}{160} \, x^{5} - \frac {95317731}{256} \, x^{4} - \frac {130251491}{384} \, x^{3} - \frac {149512931}{512} \, x^{2} - \frac {155706083}{512} \, x - \frac {156590819}{1024} \, \log \left (2 \, x - 1\right ) \]

input
integrate((2+3*x)^6*(3+5*x)^3/(1-2*x),x, algorithm="fricas")
 
output
-10125/2*x^9 - 1148175/32*x^8 - 6596235/56*x^7 - 7656993/32*x^6 - 54600291 
/160*x^5 - 95317731/256*x^4 - 130251491/384*x^3 - 149512931/512*x^2 - 1557 
06083/512*x - 156590819/1024*log(2*x - 1)
 
3.15.69.6 Sympy [A] (verification not implemented)

Time = 0.05 (sec) , antiderivative size = 70, normalized size of antiderivative = 0.97 \[ \int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx=- \frac {10125 x^{9}}{2} - \frac {1148175 x^{8}}{32} - \frac {6596235 x^{7}}{56} - \frac {7656993 x^{6}}{32} - \frac {54600291 x^{5}}{160} - \frac {95317731 x^{4}}{256} - \frac {130251491 x^{3}}{384} - \frac {149512931 x^{2}}{512} - \frac {155706083 x}{512} - \frac {156590819 \log {\left (2 x - 1 \right )}}{1024} \]

input
integrate((2+3*x)**6*(3+5*x)**3/(1-2*x),x)
 
output
-10125*x**9/2 - 1148175*x**8/32 - 6596235*x**7/56 - 7656993*x**6/32 - 5460 
0291*x**5/160 - 95317731*x**4/256 - 130251491*x**3/384 - 149512931*x**2/51 
2 - 155706083*x/512 - 156590819*log(2*x - 1)/1024
 
3.15.69.7 Maxima [A] (verification not implemented)

Time = 0.21 (sec) , antiderivative size = 52, normalized size of antiderivative = 0.72 \[ \int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx=-\frac {10125}{2} \, x^{9} - \frac {1148175}{32} \, x^{8} - \frac {6596235}{56} \, x^{7} - \frac {7656993}{32} \, x^{6} - \frac {54600291}{160} \, x^{5} - \frac {95317731}{256} \, x^{4} - \frac {130251491}{384} \, x^{3} - \frac {149512931}{512} \, x^{2} - \frac {155706083}{512} \, x - \frac {156590819}{1024} \, \log \left (2 \, x - 1\right ) \]

input
integrate((2+3*x)^6*(3+5*x)^3/(1-2*x),x, algorithm="maxima")
 
output
-10125/2*x^9 - 1148175/32*x^8 - 6596235/56*x^7 - 7656993/32*x^6 - 54600291 
/160*x^5 - 95317731/256*x^4 - 130251491/384*x^3 - 149512931/512*x^2 - 1557 
06083/512*x - 156590819/1024*log(2*x - 1)
 
3.15.69.8 Giac [A] (verification not implemented)

Time = 0.26 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.74 \[ \int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx=-\frac {10125}{2} \, x^{9} - \frac {1148175}{32} \, x^{8} - \frac {6596235}{56} \, x^{7} - \frac {7656993}{32} \, x^{6} - \frac {54600291}{160} \, x^{5} - \frac {95317731}{256} \, x^{4} - \frac {130251491}{384} \, x^{3} - \frac {149512931}{512} \, x^{2} - \frac {155706083}{512} \, x - \frac {156590819}{1024} \, \log \left ({\left | 2 \, x - 1 \right |}\right ) \]

input
integrate((2+3*x)^6*(3+5*x)^3/(1-2*x),x, algorithm="giac")
 
output
-10125/2*x^9 - 1148175/32*x^8 - 6596235/56*x^7 - 7656993/32*x^6 - 54600291 
/160*x^5 - 95317731/256*x^4 - 130251491/384*x^3 - 149512931/512*x^2 - 1557 
06083/512*x - 156590819/1024*log(abs(2*x - 1))
 
3.15.69.9 Mupad [B] (verification not implemented)

Time = 0.05 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.69 \[ \int \frac {(2+3 x)^6 (3+5 x)^3}{1-2 x} \, dx=-\frac {155706083\,x}{512}-\frac {156590819\,\ln \left (x-\frac {1}{2}\right )}{1024}-\frac {149512931\,x^2}{512}-\frac {130251491\,x^3}{384}-\frac {95317731\,x^4}{256}-\frac {54600291\,x^5}{160}-\frac {7656993\,x^6}{32}-\frac {6596235\,x^7}{56}-\frac {1148175\,x^8}{32}-\frac {10125\,x^9}{2} \]

input
int(-((3*x + 2)^6*(5*x + 3)^3)/(2*x - 1),x)
 
output
- (155706083*x)/512 - (156590819*log(x - 1/2))/1024 - (149512931*x^2)/512 
- (130251491*x^3)/384 - (95317731*x^4)/256 - (54600291*x^5)/160 - (7656993 
*x^6)/32 - (6596235*x^7)/56 - (1148175*x^8)/32 - (10125*x^9)/2